设有宏定义#define ma(x) x*(x-1)，且a=1，b=2，则ma(1+a+b)的值为多少？

ma(1+a+b)=1+a+b*(1+a+b-1) ?????????=1+1+2*(1+1+2-1); ?????????=8 宏就是简单替换，用1+a+b去替换x #define?ma(x)?x*(x-1) int??main() { ????int?a=1,?b=2; ???

?printf("%d\n",?ma(1+a+b)); ????return?0; }结果：

匿名回答于2023-09-14 04:57:20