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急,求VB判断回文数的代码?

建一个Text1,Text2,Command1。Text1,Text2的Multiline都设置为True。代码如下。

============Private Sub Command1_Click()Text2.Text = ""Dim a, i As Integer, n, s As Stringa = Split(Text1.Text, vbCrLf)For Each n In as = s & nIf n = StrReverse(n) Then s = s & "★"s = s & vbCrLfNextText2.Text = sEnd Sub

匿名回答于2024-05-21 14:33:09


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